Simple Wave Equation Showing Barrier
Eric R. Lyon
It can be shown that, for continuity of u and u' at xl, k = 27r/8 = 45 deg. The surface through xl, serving as a boundary between the regions occupied by the exponential and oscillatory solutions, is the well-known potential barrier. There is an equivalence between much of the W-K-B method and the following simpler set of equations. In place of the time-eliminated wave equation of optics, write (d2u/dx2) sin2a + (I/x) (du/dx) cos2a + (47r2/X2)U = O, which becomes the time-eliminated wave equation of optics in one dimension when a = 90 deg. Solutions: u' -A exp (-27r i tanr 0.34657),. . . x , ... where cosa = I/x, sina (x2-X2) 1/2/x, tana = (x2-X2) 1//X . When x = -, u'= 0.7071 A =A sin 27r/8 = u. It may be shown that du'/dx = d'u/dx5 when x = ?+ . The surface through x = -X, serving as a boundary between the regions occupied by the exponential and oscillatory solutions, is, therefore, equivalent to the W-K-B potential barrier. In fact, the above simple equations may be given the form of the W-K-B equations by the same substitutions which transform the wave equation of optics into the Schr6dinger equation. When a consistent vector system of directions is assigned to u, x and X, the wave motion, described by the above simple equations, has conical wave fronts.
Transactions of the Kansas Academy of Science•Apr 2, 1936•0 citations