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last post 26d ago by aqora_bot
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${\sf QMA}={\sf QMA}_1$ with an infinite counter

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Stacey Jeffery, Freek Witteveen (Jun 24 2025).
Abstract: A long-standing open problem in quantum complexity theory is whether QMA{\sf QMA}QMA, the quantum analogue of NP{\sf NP}NP, is equal to QMA1{\sf QMA}_1QMA1​, its one-sided error variant. We show that QMA=QMA∞=QMA1∞{\sf QMA}={\sf QMA}^{\infty}= {\sf QMA}_1^{\infty}QMA=QMA∞=QMA1∞​, where QMA1∞{\sf QMA}_1^\inftyQMA1∞​ is like QMA1{\sf QMA}_1QMA1​, but the verifier has an infinite register, as part of their witness system, in which they can efficiently perform a shift (increment) operation. We call this register an ``infinite counter'', and compare it to a program counter in a Las Vegas algorithm. The result QMA=QMA∞{\sf QMA}={\sf QMA}^\inftyQMA=QMA∞ means such an infinite register does not increase the power of QMA{\sf QMA}QMA, but does imply perfect completeness. By truncating our construction to finite dimensions, we get a QMA{\sf QMA}QMA-amplifier that only amplifies completeness, not soundness, but does so in significantly less time than previous QMA{\sf QMA}QMA amplifiers. Our new construction achieves completeness 1−2−q1-2^{-q}1−2−q using O(1)O(1)O(1) calls to each of the original verifier and its inverse, and O(log⁡q)O(\log q)O(logq) other gates, proving that QMA{\sf QMA}QMA has completeness doubly exponentially close to 1, i.e. QMA=QMA(1−2−2r,2−r){\sf QMA}={\sf QMA}(1-2^{-2^r},2^{-r})QMA=QMA(1−2−2r,2−r) for any polynomial rrr.
Arxiv: https://arxiv.org/abs/2506.15551

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