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arXiv:quant-ph/0603009 · Journal of Algebra

Deciding universality of quantum gates

Gábor Ivanyos

Published Oct 24, 2006• 1 citation
arXivHTMLPDF
DOI
10.1016/j.jalgebra.2006.09.013

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We consider the problem of deciding if a set of quantum one-qudit gates S={g1,…,gn}⊂G\mathcal {S}=\{g_1,\ldots ,g_n\}\subset GS={g1​,…,gn​}⊂G is universal, i.e. if <S>{<}\mathcal {S}{>}<S> is dense in G, where G is either the special unitary or the special orthogonal group. To every gate g in S\mathcal {S}S we assign the orthogonal matrix Adg\mathrm {Ad}_gAdg​ that is image of g under the adjoint representation Ad:G→SO(g)\mathrm {Ad}:G\rightarrow SO(\mathfrak {g})Ad:G→SO(g) and g\mathfrak {g}g is the Lie algebra of G. The necessary condition for the universality of S\mathcal {S}S is that the only matrices that commute with all Adgi\mathrm {Ad}_{g_i}Adgi​​ ’s are proportional to the identity. If in addition there is an element in <S>{<}\mathcal {S}{>}<S> whose Hilbert–Schmidt distance from the centre of G belongs to ]0,12[]0,\frac{1}{\sqrt{2}}[]0,2​1​[ , then S\mathcal {S}S is universal. Using these we provide a simple algorithm that allows deciding the universality of any set of d-dimensional gates in a finite number of steps and formulate a general classification theorem.
We present a criterion that serves as the basis for a polynomial-time algorithm to decide whether a finite set of qudit gates exponentiated by some Hamiltonians is universal. Our approach formulates universality in Lie algebraic terms and applies Borel--de Siebenthal theory with a diagonal generator having incommensurate spectrum. In this framework, nonuniversality is detected by invariant subspaces, equivalently by a graph-connectivity obstruction, while universality is repaired by adding generators that couple disconnected components. We further prove that two generators are sufficient for universal control. Our work reveals a profound link between qudit universality and irreducibility of Lie algebra representations.