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arXiv:quant-ph/0410206 · Physical Review A

Solution to the king’s problem with observables that are not mutually complementary

M. Horibe, A. Hayashi, T. Hashimoto

Published Mar 23, 2005• 7 citations
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Abstract

We investigate the king's problem of the measurement of operators ${\stackrel{P\vec}{n}}_{k}∙\stackrel{P\vec}{\ensuremath{\sigma}}$ ($k=1$, 2, 3) instead of the three Cartesian components ${\ensuremath{\sigma}}_{x},{\ensuremath{\sigma}}_{y}$, and ${\ensuremath{\sigma}}_{z}$ of the spin operator $\stackrel{P\vec}{\ensuremath{\sigma}}$. Here, ${\stackrel{P\vec}{n}}_{k}$ are three-dimensional real unit vectors. We show the condition over three vectors ${\stackrel{P\vec}{n}}_{k}$ to ascertain the result for measurement of any one of these operators.

DOI
10.1103/physreva.71.032337

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We investigate the king's problem of the measurement of operators {\stackrel{P\vec}{n}}_{k}∙\stackrel{P\vec}{\ensuremath{\sigma}} (k=1k=1k=1, 2, 3) instead of the three Cartesian components \ensuremathσx,\ensuremathσy{\ensuremath{\sigma}}_{x},{\ensuremath{\sigma}}_{y}\ensuremathσx​,\ensuremathσy​, and \ensuremathσz{\ensuremath{\sigma}}_{z}\ensuremathσz​ of the spin operator \stackrel{P\vec}{\ensuremath{\sigma}}. Here, {\stackrel{P\vec}{n}}_{k} are three-dimensional real unit vectors. We show the condition over three vectors {\stackrel{P\vec}{n}}_{k} to ascertain the result for measurement of any one of these operators.
The Mean King's problem asks to determine the outcome of a measurement that is randomly selected from a set of complementary observables. We review this problem and offer a combinatorial solution. More generally, we show that whenever an affine resolvable design exists, then a state reconstruction problem similar to the Mean King's problem can be defined and solved. As an application of this general framework we consider a problem involving three qubits in which the outcome of nine different measurements can be determined without using ancillary qubits. The solution is based on a measurement derived from Hadamard designs.