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arXiv:cs/0611082

The Computational Complexity of the Traveling Salesman Problem

Craig Alan Feinstein

Published Nov 17, 2006• 4 citations
arXivHTMLPDF

Abstract

In this note, we show that the Traveling Salesman Problem cannot be solved in polynomial-time on a classical computer.
DOI
10.48550/arxiv.cs/0611082

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Study On Adaptive Quantum Algorithm In Traveling Salesman Problem

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Quantum Divide-and-Conquer for the Traveling Salesman Problem: Surpassing the 2n2^n2n Barrier
The traveling salesman problem (TSP) is a classic NP-hard problem. Held--Karp dynamic programming~\cite{held1962dynamic, bellman1962dynamic} solves it exactly in O(n22n)O(n^2 2^n)O(n22n) time, a barrier that has stood for over six decades. Whether quantum computing can surpass O∗(2n)O^*(2^n)O∗(2n) is a central open question. The authors of~\cite{ambainis2019quantum}\ (SODA~2019) claimed a query complexity of O∗(1.727n)O^*(1.727^n)O∗(1.727n), but we identify a structural counting error: when corrected, their scheme requires Ω∗(2n)Ω^*(2^n)Ω∗(2n) queries and offers no advantage over classical Held--Karp. We design a quantum divide-and-conquer framework: partition nnn-vertex set into kkk subsets, classically precompute shortest paths within each, then search over all kkk-partitions via quantum minimum finding. We prove k=3k=3k=3 achieves O∗(1.890n)O^*(1.890^n)O∗(1.890n), and k=4k=4k=4 attains the global optimum O∗(1.866n)O^*(1.866^n)O∗(1.866n), the first quantum algorithm to surpass O∗(2n)O^*(2^n)O∗(2n) for general TSP. To convert the query bound into a time-complexity advantage, we overcome the oracle-construction bottleneck by preparing a set partition state, requiring O(n2)O(n^2)O(n2) gates and O(n)O(n)O(n) depth. Leveraging structured state preparation, we achieve a total time complexity of O∗(1.866n)O^*(1.866^n)O∗(1.866n). Qiskit simulations on n=6,7n=6,7n=6,7 achieve 98.9%98.9\%98.9% and 100%100\%100% accuracy.