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P=NP via Factorization and Shor's Algorithm

יהוה, Kaoru Aguilera Katayama

Published Feb 11, 2026• 0 citations
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Abstract

We prove $P = NP$ by showing that Integer Factorization is NP-Complete and that Shor's algorithm solves it in $O(\log\ n)$.

DOI
10.5281/zenodo.18604587

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We prove P=NPP = NPP=NP by showing that Integer Factorization is NP-Complete and that Shor's algorithm solves it in O(log⁡ n)O(\log\ n)O(log n).