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Physical Review

Linear Magnetic Chains with Anisotropic Coupling

Jill C. Bonner, Michael Ellis Fisher

Published Aug 3, 1964• 2,497 citations
Publisher

Abstract

Linear chains (and rings) of $S=\frac{1}{2}$ spins with the anisotropic (Ising-Heisenberg) Hamiltonian $\mathcal{H}=\ensuremath{-}2J\ensuremath{\Sigma}\stackrel{N}{i=1}{{{S}_{i}}^{z}{{S}_{i+1}}^{z}+\ensuremath{\gamma}({{S}_{i}}^{x}{{S}_{i+1}}^{x}+{{S}_{i}}^{y}{{S}_{i+1}}^{y})}\ensuremath{-}g\ensuremath{\beta}\ensuremath{\Sigma}\stackrel{N}{i=1}\mathrm{H}\ifmmode\cdot\else\textperiodcentered\fi{}{\mathrm{S}}_{i}$ have been studied by exact machine calculations for $N=2 \mathrm{to} 11$, $\ensuremath{\gamma}=0 \mathrm{to} 1$ and for ferro- and antiferro-magnetic coupling. The results reveal the dependence on finite size and anisotropy of the spectrum and dispersion laws, of the energy, entropy, and specific heat, of the magnetization and susceptibilities, and of the pair correlations. The limiting $N\ensuremath{\rightarrow}\ensuremath{\infty}$ behavior is accurately indicated, for all $\ensuremath{\gamma}$, in the region $\frac{\mathrm{kT}}{|J|}>~0.5$ which includes the maxima in the specific heat and susceptibility. The behavior of thermal and magnetic properties of infinite chains at lower temperatures is estimated by extrapolation. For infinite antiferromagnetic chains the ground-state degeneracy, the anisotropy gap, and the magnetization, perpendicular susceptibility, and pair correlations at $T=0$ are similarly studied. Estimates of the long-range order suggest that it vanishes only at the Heisenberg limit $\ensuremath{\gamma}=1$ and confirm the accuracy of Walker's perturbation series in $\ensuremath{\gamma}$.

DOI
10.1103/physrev.135.a640

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The exact eigenvalue spectrum and thermodynamic properties of the spin Hamiltonian $\mathcal{H}=2|J|\ensuremath{\Sigma}\stackrel{\frac{N}{2}}{i=1}({\mathrm{S}}_{2i}\ifmmode\cdot\else\textperiodcentered\fi{}{\mathrm{S}}_{2i\ensuremath{-}1}+a{\mathrm{S}}_{2i}\ifmmode\cdot\else\textperiodcentered\fi{}{\mathrm{S}}_{2i+1})$ are calculated for short chains of N=4,6,8,and10N=4,6,8, \mathrm{and} 10N=4,6,8,and10 spins, each of spin \textonehalf{}, for alternation parameter a=0.2,0.4,0.6,and0.8a=0.2,0.4,0.6, \mathrm{and} 0.8a=0.2,0.4,0.6,and0.8, with ${\mathrm{S}}_{N+1}\ensuremath{\equiv}{\mathrm{S}}_{1}$. The behavior for $N=\ensuremath{\infty}$ is estimated by extrapolation. Comparison is made with the known results for a=0a=0a=0 and 1. The ground-state energy, ground-state short-range order, energy gap, and triplet excitation spectrum are compared with various approximate theories. Zero-temperature infinite-chain magnetization curves are inferred from the finite-chain results. The energy, entropy, specific heat, and magnetic susceptibility for N=10N=10N=10 are shown to approximate well the behavior for $N=\ensuremath{\infty}$ when kT∣J∣>a\frac{\mathrm{kT}}{|J|}>a∣J∣kT​>a. The magnetic-susceptibility data on the free radical 2,2-bis (ppp-nitrophenyl)-1-picrylhydrazyl are shown to agree well with the theoretical results for an alternating chain with $a\ensuremath{\approx}0.6$.
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The Heisenberg-Ising Hamiltonian has been exactly solved us- ing the Lanczos method, for chain of up to N = 28 spins. In the whole anisotropic region, the mass gap displays a dominant exponential behavior with size. The extrapolated ground state is doubly degenerate, and presents long-range order with dominant components of the Neel type. Quantum fluctuations become more important as long as the anisotropy is reduced, leading to a disordered singlet ground state for the infinite system at the isotropic point.
The anisotropic Hamiltonian, $H=\ensuremath{-}\frac{1}{2}\ensuremath{\Sigma}({J}_{x}{{\ensuremath{\sigma}}_{l}}^{x}{{\ensuremath{\sigma}}_{l+1}}^{x}+{J}_{y}{{\ensuremath{\sigma}}_{l}}^{y}{{\ensuremath{\sigma}}_{l+1}}^{y}+{J}_{z}{{\ensuremath{\sigma}}_{l}}^{z}{{\ensuremath{\sigma}}_{l+1}}^{z})\ensuremath{-}m\mathcal{H}\ensuremath{\Sigma}{{\ensuremath{\sigma}}_{l}}^{z},$ of the linear spin array in the Heisenberg model of magnetism is examined. The eigenstate and the partition function for the case Jz=0{J}_{z}=0Jz​=0 are obtained exactly for a finite system and for an infinite system with the aid of annihilation and creation operators, and the free energy FFF of the latter is given by $\ensuremath{-}\frac{F}{\mathrm{NkT}}=(\frac{1}{\ensuremath{\pi}})\ensuremath{\int}{0}^{\ensuremath{\pi}}\mathrm{ln}{2cosh{[{{K}_{x}}^{2}+{{K}_{y}}^{2}+2{K}_{x}{K}_{y}cos2\ensuremath{\omega}\ensuremath{-}2C({K}_{x}+{K}_{y})cos\ensuremath{\omega}+{C}^{2}]}^{\frac{1}{2}}}d\ensuremath{\omega},$ where Kx=Jx2kT{K}_{x}=\frac{{J}_{x}}{2kT}Kx​=2kTJx​​, Ky=Jy2kT{K}_{y}=\frac{{J}_{y}}{2kT}Ky​=2kTJy​​, C=mHkTC=\frac{m\mathcal{H}}{\mathrm{kT}}C=kTmH​. The case Jx=Jy=Jz=J{J}_{x}={J}_{y}={J}_{z}=JJx​=Jy​=Jz​=J is discussed with the aid of a high-temperature expansion and of analysis of small systems. Specific heats and susceptibilities in special cases: (i) Jx=Jy=J{J}_{x}={J}_{y}=JJx​=Jy​=J, Jz=0{J}_{z}=0Jz​=0, (ii) Jx=J{J}_{x}=JJx​=J, Jy=Jz=0{J}_{y}={J}_{z}=0Jy​=Jz​=0, (iiif{\mathrm{iii}}_{\mathrm{f}}iiif​) Jx=Jy=0{J}_{x}={J}_{y}=0Jx​=Jy​=0, Jz=J>0{J}_{z}=J>0Jz​=J>0, (iiia{\mathrm{iii}}_{\mathrm{a}}iiia​) Jx=Jy=0{J}_{x}={J}_{y}=0Jx​=Jy​=0, Jz=J<0{J}_{z}=J<0Jz​=J<0, (ivf{\mathrm{iv}}_{\mathrm{f}}ivf​) Jx=Jy=Jz=J>0{J}_{x}={J}_{y}={J}_{z}=J>0Jx​=Jy​=Jz​=J>0, (iva{\mathrm{iv}}_{\mathrm{a}}iva​) Jx=Jy=Jz=J<0{J}_{x}={J}_{y}={J}_{z}=J<0Jx​=Jy​=Jz​=J<0 are compared and it is shown that (i), (iiia{\mathrm{iii}}_{\mathrm{a}}iiia​), and (iva{\mathrm{iv}}_{\mathrm{a}}iva​) have the characteristic features of the observed parallel susceptibility of an antiferromagnetic substance, (ii) those of perpendicular susceptibility, and (iiif{\mathrm{iii}}_{\mathrm{f}}iiif​) and (ivf{\mathrm{iv}}_{\mathrm{f}}ivf​) those of paramagnetic susceptibility, even though they have no singularities. The distribution of the zeros of the partition function is also discussed.
The exact solution is given for a linear chain of NNN atoms of spin \textonehalf{} coupled together by the anisotropic Hamiltonian $\mathcal{H}=2J\ensuremath{\Sigma}\stackrel{N}{i=1}[{{S}_{i}}^{z}{{S}_{i+1}}^{z}+(1\ensuremath{-}\ensuremath{\alpha})({{S}_{i}}^{x}{{S}_{i+1}}^{x}+{{S}_{i}}^{y}{{S}_{i+1}}^{y})].$ The energy of the antiferromagnetic ground state is computed and comparison is made with a variational method. The parameter $\ensuremath{\alpha}$ is allowed to vary between 0 and 1, regulating the relative amount of Ising anisotropy. The short-range order, $\ensuremath{\Sigma}{i}^{}{{S}_{i}}^{z}{{S}_{i+1}}^{z}$, is calculated exactly from the variation of the ground-state energy with $\ensuremath{\alpha}$. It is shown that a kink in the short-range order curve calculated using the variational method is fictitious, and the associated discontinuity in $\frac{{\ensuremath{\partial}}^{2}E}{\ensuremath{\partial}{\ensuremath{\alpha}}^{2}}$ is nonexistent. A discussion is given of long-range order and criticisms are presented regarding the predictions of the variational method.