Challenges
Datasets
Workspaces
Papers
Discussions
Leaderboard
Log inSign up
Challenges
Datasets
Workspaces
Papers
Discussions
Leaderboard
Blog
Job Board
Q3AS

© 2026 Aqora Quantum S.A.S.

TermsPrivacyLegal Notice

The New Scientist

Time to decide

Nicolas Gisin

Published May 1, 2016• 2 citations
Publisher
DOI
10.1016/s0262-4079(16)30904-6

Related papers

Time and space efficient quantum algorithms for detecting cycles and testing bipartiteness

Chris Cade, Ashley Montanaro, Aleksandrs Belovs

We study space and time-efficient quantum algorithms for two graph problems – deciding whether an n-vertex graph is a forest, and whether it is bipartite. Via a reduction to the s-t connectivity problem, we describe quantum algorithms for deciding both properties in O˜(n 3/2 ) time whilst using O(log n) classical and quantum bits of storage in the adjacency matrix model. We then present quantum algorithms for deciding the two properties in the adjacency array model, which run in time O˜(n √ dm) and also require O(log n) space, where dm is the maximum degree of any vertex in the input graph.

arXiv:1610.00581•Quantum Information and Computation•Feb 1, 2018•7 citations

Time to think

Mark Buchanan

Nature Physics•Dec 1, 2013•0 citations

A Polynomial-Time Algorithm for the Equivalence between Quantum Sequential Machines

Lvzhou Li, Daowen Qiu

Quantum sequential machines (QSMs) are a quantum version of stochastic sequential machines (SSMs). Recently, we showed that two QSMs M_1 and M_2 with n_1 and n_2 states, respectively, are equivalent iff they are (n_1+n_2)^2--equivalent (Theoretical Computer Science 358 (2006) 65-74). However, using this result to check the equivalence likely needs exponential expected time. In this paper, we consider the time complexity of deciding the equivalence between QSMs and related problems. The main results are as follows: (1) We present a polynomial-time algorithm for deciding the equivalence between QSMs, and, if two QSMs are not equivalent, this algorithm will produce an input-output pair with length not more than (n_1+n_2)^2. (2) We improve the bound for the equivalence between QSMs from (n_1+n_2)^2 to n_1^2+n_2^2-1, by employing Moore and Crutchfield's method (Theoretical Computer Science 237 (2000) 275-306). (3) We give that two MO-1QFAs with n_1 and n_2 states, respectively, are equivalent iff they are (n_1+n_2)^2--equivalent, and further obtain a polynomial-time algorithm for deciding the equivalence between two MO-1QFAs. (4) We provide a counterexample showing that Koshiba's method to solve the problem of deciding the equivalence between MM-1QFAs may be not valid, and thus the problem is left open again.

arXiv:quant-ph/0604085•Apr 12, 2006•2 citations

The Choice

Daniel Kleppner

Physics Today•Oct 1, 1995•3 citations

3XOR Games with Perfect Commuting Operator Strategies Have Perfect Tensor Product Strategies and are Decidable in Polynomial Time

Adam Bene Watts, J. William Helton

Abstract We consider 3XOR games with perfect commuting operator strategies. Given any 3XOR game, we show existence of a perfect commuting operator strategy for the game can be decided in polynomial time. Previously this problem was not known to be decidable. Our proof leads to a construction, showing a 3XOR game has a perfect commuting operator strategy iff it has a perfect tensor product strategy using a 3 qubit (8 dimensional) GHZ state. This shows that for perfect 3XOR games the advantage of a quantum strategy over a classical strategy (defined by the quantum-classical bias ratio) is bounded. This is in contrast to the general 3XOR case where the optimal quantum strategies can require high dimensional states and there is no bound on the quantum advantage. To prove these results, we first show equivalence between deciding the value of an XOR game and solving an instance of the subgroup membership problem on a class of right angled Coxeter groups. We then show, in a proof that consumes most of this paper, that the instances of this problem corresponding to 3XOR games can be solved in polynomial time.

arXiv:2010.16290•Communications in Mathematical Physics•Feb 10, 2023•2 citations

Second thoughts

Malcolm A. McCausland

Physics World•Aug 1, 1997•0 citations
We study space and time-efficient quantum algorithms for two graph problems – deciding whether an n-vertex graph is a forest, and whether it is bipartite. Via a reduction to the s-t connectivity problem, we describe quantum algorithms for deciding both properties in O˜(n 3/2 ) time whilst using O(log n) classical and quantum bits of storage in the adjacency matrix model. We then present quantum algorithms for deciding the two properties in the adjacency array model, which run in time O˜(n √ dm) and also require O(log n) space, where dm is the maximum degree of any vertex in the input graph.
Quantum sequential machines (QSMs) are a quantum version of stochastic sequential machines (SSMs). Recently, we showed that two QSMs M_1 and M_2 with n_1 and n_2 states, respectively, are equivalent iff they are (n_1+n_2)^2--equivalent (Theoretical Computer Science 358 (2006) 65-74). However, using this result to check the equivalence likely needs exponential expected time. In this paper, we consider the time complexity of deciding the equivalence between QSMs and related problems. The main results are as follows: (1) We present a polynomial-time algorithm for deciding the equivalence between QSMs, and, if two QSMs are not equivalent, this algorithm will produce an input-output pair with length not more than (n_1+n_2)^2. (2) We improve the bound for the equivalence between QSMs from (n_1+n_2)^2 to n_1^2+n_2^2-1, by employing Moore and Crutchfield's method (Theoretical Computer Science 237 (2000) 275-306). (3) We give that two MO-1QFAs with n_1 and n_2 states, respectively, are equivalent iff they are (n_1+n_2)^2--equivalent, and further obtain a polynomial-time algorithm for deciding the equivalence between two MO-1QFAs. (4) We provide a counterexample showing that Koshiba's method to solve the problem of deciding the equivalence between MM-1QFAs may be not valid, and thus the problem is left open again.
Abstract We consider 3XOR games with perfect commuting operator strategies. Given any 3XOR game, we show existence of a perfect commuting operator strategy for the game can be decided in polynomial time. Previously this problem was not known to be decidable. Our proof leads to a construction, showing a 3XOR game has a perfect commuting operator strategy iff it has a perfect tensor product strategy using a 3 qubit (8 dimensional) GHZ state. This shows that for perfect 3XOR games the advantage of a quantum strategy over a classical strategy (defined by the quantum-classical bias ratio) is bounded. This is in contrast to the general 3XOR case where the optimal quantum strategies can require high dimensional states and there is no bound on the quantum advantage. To prove these results, we first show equivalence between deciding the value of an XOR game and solving an instance of the subgroup membership problem on a class of right angled Coxeter groups. We then show, in a proof that consumes most of this paper, that the instances of this problem corresponding to 3XOR games can be solved in polynomial time.