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Journal of Physics A Mathematical and General

Comment on $lquot$Integrable Kondo impurity in one-dimensional q-deformed t$ndash$J models$rquot$

P. Schlottmann, Andrei A. Zvyagin

Published Jul 12, 2002• 3 citations
Publisher

Abstract

The relation between integrable magnetic impurities located at the boundary and embedded into a one-dimensional correlated electron chain is discussed. Misleading statements by Ge et al are corrected and placed into proper context.
DOI
10.1088/0305-4470/35/29/402

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Comment on lquotlquotlquotIntegrable Kondo impurity in one-dimensional q-deformed tndashndashndashJ modelsrquotrquotrquot
Integrable Kondo impurity in one-dimensional q-deformed t−Jt-Jt−J models
Integrable Kondo impurities in two cases of the one-dimensional q-deformed t−Jt-Jt−J models are studied by means of the boundary Z2{\bf Z}_2Z2​-graded quantum inverse scattering method. The boundary KKK matrices depending on the local magnetic moments of the impurities are presented as nontrivial realizations of the reflection equation algebras in an impurity Hilbert space. Furthermore, these models are solved by using the algebraic Bethe ansatz method and the Bethe ansatz equations are obtained.
Reply to comment on lquotlquotlquotIntegrable Kondo impurity in one-dimensional q-deformed tndashndashndashJ modelsrquotrquotrquot
The Kondo problem of two impurities in a 1D strongly correlated electron system within the framework of the open boundary Hubbard chain is solved and the impurities, coupled to the ends of the electron system, are introduced by their scattering matrices with electrons so that the boundary matrices satisfy the reflecting integrability condition. The finite-size correction of the ground-state energy is obtained due to the impurities. Exact expressions for the low-temperature specific heat contributed by the charge and spin parts of the magnetic impurities are derived. The Pauli susceptibility and the Kondo temperature are given explicitly. The Kondo temperature is inversely proportional to the density of electrons.