arXiv:1801.08393
Three level Lambda system, Feynman amplitudes and relativistic invariance
Navin Khaneja
Abstract
In this paper, we develop an analogy between the three level atomic system so called Lambda system and scattering processes in quantum electrodynamics (QED). In a Lambda system we have two ground state levels $|1 \rangle$ and $|3 \rangle$ at energy $E_1$ and excited level $|2 \rangle$ at energy $E_2$. The transition from $|1 \rangle$ to $|2 \rangle$ has strength $\Omega_1$ and transition from $|2 \rangle$ to $|3 \rangle$ has strength $\Omega_2$. When we adiabatically eliminate the excited state, i.e. go in the interaction frame of natural Hamiltonian of the system, we get a second order term connecting level $|1 \rangle$ to $|3 \rangle$ with strength $\frac{\Omega_1\Omega_2}{2(E_1-E_2)}$. This term creates an effective coupling between ground state levels and drives transition from $|1 \rangle$ to $| 3\rangle$. Scattering processes in QED can be modelled like this. Feynman amplitudes are calculation of second order term ${\cal M} = \frac{\Omega_1\Omega_2}{2(E_1-E_2)}$. In the rest frame $O'$ ({\bf CM} frame) where sum of momentum of incoming particles is $0$, if the Feynman amplitude is ${\cal M'}$, then in a frame $O$ in which $O'$ moves with velocity $v$ , the time gets dilated to $t = \frac{t'}{\sqrt{1-\frac{v^2}{c^2}}}$ and hence it must be true that ${\cal M} = {\cal M'} \sqrt{1-\frac{v^2}{c^2}}$. We show that to make this relativistic invariance of $\mathcal{M}$ to work, we have to modify the QED interaction Hamiltonian. Using this modification, we calculate the scattering amplitude for QED processes, Compton scattering and M{\o}ller Scattering.