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arXiv:1801.03285

A Composition Theorem via Conflict Complexity

Swagato Sanyal

Published Jan 10, 2018• 4 citations
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Abstract

Let $\R(\cdot)$ stand for the bounded-error randomized query complexity. We show that for any relation $f \subseteq \{0,1\}^n \times \mathcal{S}$ and partial Boolean function $g \subseteq \{0,1\}^n \times \{0,1\}$, $\R_{1/3}(f \circ g^n) = Ω(\R_{4/9}(f) \cdot \sqrt{\R_{1/3}(g)})$. Independently of us, Gavinsky, Lee and Santha \cite{newcomp} proved this result. By an example demonstrated in their work, this bound is optimal. We prove our result by introducing a novel complexity measure called the \emph{conflict complexity} of a partial Boolean function $g$, denoted by $χ(g)$, which may be of independent interest. We show that $χ(g) = Ω(\sqrt{\R(g)})$ and $\R(f \circ g^n) = Ω(\R(f) \cdot χ(g))$.

DOI
10.48550/arxiv.1801.03285

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Let R(⋅)\R(\cdot)R(⋅) stand for the bounded-error randomized query complexity. We show that for any relation f⊆{0,1}n×Sf \subseteq \{0,1\}^n \times \mathcal{S}f⊆{0,1}n×S and partial Boolean function g⊆{0,1}n×{0,1}g \subseteq \{0,1\}^n \times \{0,1\}g⊆{0,1}n×{0,1}, R1/3(f∘gn)=Ω(R4/9(f)⋅R1/3(g))\R_{1/3}(f \circ g^n) = Ω(\R_{4/9}(f) \cdot \sqrt{\R_{1/3}(g)})R1/3​(f∘gn)=Ω(R4/9​(f)⋅R1/3​(g)​). Independently of us, Gavinsky, Lee and Santha \cite{newcomp} proved this result. By an example demonstrated in their work, this bound is optimal. We prove our result by introducing a novel complexity measure called the \emph{conflict complexity} of a partial Boolean function ggg, denoted by χ(g)χ(g)χ(g), which may be of independent interest. We show that χ(g)=Ω(R(g))χ(g) = Ω(\sqrt{\R(g)})χ(g)=Ω(R(g)​) and R(f∘gn)=Ω(R(f)⋅χ(g))\R(f \circ g^n) = Ω(\R(f) \cdot χ(g))R(f∘gn)=Ω(R(f)⋅χ(g)).
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For any relation f subseteq {0,1}^n x S and any partial Boolean function g:{0,1}^m -> {0,1,*}, we show that R_{1/3}(f o g^n) in Omega(R_{4/9}(f) * sqrt{R_{1/3}(g)}) , where R_epsilon(*) stands for the bounded-error randomized query complexity with error at most epsilon, and f o g^n subseteq ({0,1}^m)^n x S denotes the composition of f with n instances of g. The new composition theorem is optimal, at least, for the general case of relational problems: A relation f_0 and a partial Boolean function g_0 are constructed, such that R_{4/9}(f_0) in Theta(sqrt n), R_{1/3}(g_0)in Theta(n) and R_{1/3}(f_0 o g_0^n) in Theta(n). The theorem is proved via introducing a new complexity measure, max-conflict complexity, denoted by bar{chi}(*). Its investigation shows that bar{chi}(g) in Omega(sqrt{R_{1/3}(g)}) for any partial Boolean function g and R_{1/3}(f o g^n) in Omega(R_{4/9}(f) * bar{chi}(g)) for any relation f, which readily implies the composition statement. It is further shown that bar{chi}(g) is always at least as large as the sabotage complexity of g.
Let the randomized query complexity of a relation for error probability εεε be denoted by Rε(⋅)R_ε(\cdot)Rε​(⋅). We prove that for any relation f⊆{0,1}n×Rf \subseteq \{0,1\}^n \times \mathcal{R}f⊆{0,1}n×R and Boolean function g:{0,1}m→{0,1}g:\{0,1\}^m \rightarrow \{0,1\}g:{0,1}m→{0,1}, R1/3(f∘gn)=Ω(R4/9(f)⋅R1/2−1/n4(g))R_{1/3}(f\circ g^n) = Ω(R_{4/9}(f)\cdot R_{1/2-1/n^4}(g))R1/3​(f∘gn)=Ω(R4/9​(f)⋅R1/2−1/n4​(g)), where f∘gnf \circ g^nf∘gn is the relation obtained by composing fff and ggg. We also show that R1/3(f∘(gO(log⁡n)⊕)n)=Ω(log⁡n⋅R4/9(f)⋅R1/3(g))R_{1/3}\left(f \circ \left(g^\oplus_{O(\log n)}\right)^n\right)=Ω(\log n \cdot R_{4/9}(f) \cdot R_{1/3}(g))R1/3​(f∘(gO(logn)⊕​)n)=Ω(logn⋅R4/9​(f)⋅R1/3​(g)), where gO(log⁡n)⊕g^\oplus_{O(\log n)}gO(logn)⊕​ is the function obtained by composing the xor function on O(log⁡n)O(\log n)O(logn) bits and gtg^tgt.
Let the randomized query complexity of a relation for error probability epsilon be denoted by R_epsilon(). We prove that for any relation f contained in {0,1}^n times R and Boolean function g:{0,1}^m -> {0,1}, R_{1/3}(f o g^n) = Omega(R_{4/9}(f).R_{1/2-1/n^4}(g)), where f o g^n is the relation obtained by composing f and g. We also show using an XOR lemma that R_{1/3}(f o (g^{xor}_{O(log n)})^n) = Omega(log n . R_{4/9}(f) . R_{1/3}(g))$, where g^{xor}_{O(log n)} is the function obtained by composing the XOR function on O(log n) bits and g.
For a (possibly partial) Boolean function f ⁣:{0,1}n→{0,1}f\colon\{0,1\}^n\to\{0,1\}f:{0,1}n→{0,1} as well as a query complexity measure MMM which maps Boolean functions to real numbers, define the composition limit of MMM on fff by M∗(f)=lim⁡k→∞M(fk)1/kM^*(f)=\lim_{k\to\infty} M(f^k)^{1/k}M∗(f)=limk→∞​M(fk)1/k. We study the composition limits of general measures in query complexity. We show this limit converges under reasonable assumptions about the measure. We then give a surprising result regarding the composition limit of randomized query complexity: we show R0∗(f)=max⁡{R∗(f),C∗(f)}R_0^*(f)=\max\{R^*(f),C^*(f)\}R0∗​(f)=max{R∗(f),C∗(f)}. Among other things, this implies that any bounded-error randomized algorithm for recursive 3-majority can be turned into a zero-error randomized algorithm for the same task. Our result extends also to quantum algorithms: on recursively composed functions, a bounded-error quantum algorithm can be converted into a quantum algorithm that finds a certificate with high probability. Along the way, we prove various combinatorial properties of measures and composition limits.
A longstanding open question in Boolean function complexity asks whether approximate degree composes multiplicatively under block composition. Although a general multiplicative upper bound is known, matching lower bounds have previously been established only for restricted classes of functions. We resolve this question for all total Boolean functions by proving the matching lower bound. Together with Sherstov's upper bound, our result shows that, for every pair of total Boolean functions f:{0,1}n→{0,1}f:\{0,1\}^n\to\{0,1\}f:{0,1}n→{0,1} and g:{0,1}m→{0,1}g:\{0,1\}^m\to\{0,1\}g:{0,1}m→{0,1}, deg~(f∘g)=Θ ⁣(deg~(f) deg~(g)), \widetilde{deg}(f\circ g) = Θ\!\left( \widetilde{deg}(f)\,\widetilde{deg}(g) \right), deg​(f∘g)=Θ(deg​(f)deg​(g)), where deg~\widetilde{deg}deg​ denotes constant-error approximate degree. We also consider the analogous question for exact quantum query complexity and give a counterexample showing that multiplicative composition fails in this setting.